How many watts can a 15a breaker take on a 115v service?
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multiply the volts times the amps and this will give you the full load watts.then you need to divide the watts by 80% to determine optimal load watts to keep from overheating your wire and breaker.so 115 x 15 = 1725 divided by 80% =1380 watts. if you pulled the complete 1725 watts the breaker would not last to long due to overheating...the national electric code states you shall not exceed 80% use of the name plate amps of any breaker or fuse..so 80% of 15 amps is 12 amps
3 and that is unsafe
A 15amp breaker can be loaded to 1380 watts. This is 80% of the full rating of the breaker.
1725 Watts
The formula is W=Amps x Volts. That makes it 1725 watts by my calculations.
My husband says to go to home depoe and get a book called uglys book it shows you how to figure out all your electial stuff...he says to be safe no more than 1700, and it is always best to be safe.hope it helps
American electrical distribution systems run at 120/240 Volts. Therefore the total wattage available would be computed by 15 Amps multiplied by 120 Volts equaling 1800 Amps.
If the load is rated as continuous, that would be three hours or more in duration, the circuit would have to be derated to 80 percent of the full load or 1440 Watts. For most uses, it would be hard to get enough wattage in use to exceed the 1440 long enough to make a difference. However, a couple of hairdryers, a toaster in the microwave, a lot of ordinary household appliances used together can add up to more than the 1800 Watts and should trip the breaker.
If you are having breakers trip frequently it would be important to have a qualified electrician check your system for safety.
electrical loading according to electrical code shall be 80% of 15 amp or 12 amp (12*115 watts)
1725 watts would be the maximum provided that it is the only item on the circuit and a provision for some extra. Watts = Volts X Amps
15 X 115 = 1725 watts X 80%= 1380
voltage actually measures 120Volts x15=1800x 80%=1440 watts
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